CALLING ALL MATH GEEKS QQ (Algebra II here)
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CALLING ALL MATH GEEKS QQ (Algebra II here)
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Jaehyo Posts : 64
Join date : 20120724
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
Jaehyo wrote:[You must be registered and logged in to see this image.]
3^3 * y^4 * y^2=
27 * y^(4+2)=
27*y^6
Eisenmeteor Posts : 27
Join date : 20120714
Age : 27
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
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Jaehyo Posts : 64
Join date : 20120724
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
Jaehyo wrote:[You must be registered and logged in to see this image.]
(3^7 / 3^3) * (x^5 / x^3)
[3^(73)] * [x^(53)]
3^4 * x^2
81*x²
Eisenmeteor Posts : 27
Join date : 20120714
Age : 27
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
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Jaehyo Posts : 64
Join date : 20120724
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
2/3 a^7 b^1
6 (a^(3*3) b^(1*3))
3^2 a^(1*2) b^(1*2)
6 a^9 b^3
9 a^2 b^2
6/9 a^(92) b^(32)
2/3 a^7 b
6 (a^(3*3) b^(1*3))
3^2 a^(1*2) b^(1*2)
6 a^9 b^3
9 a^2 b^2
6/9 a^(92) b^(32)
2/3 a^7 b
Last edited by Kaze on Wed Aug 22, 2012 2:56 am; edited 1 time in total
Kaze Posts : 10
Join date : 20120718
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
Jaehyo wrote:[You must be registered and logged in to see this image.]
6[a^(3*3)*b³] / (3²*a²*b²)
6(a^9*b³) / (9*a²*b²)
6/9 * (a^9) / a² * b³/b²
2/3 * a^7 * b
(2*a^7*b)/3
Eisenmeteor Posts : 27
Join date : 20120714
Age : 27
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
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Jaehyo Posts : 64
Join date : 20120724
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
Jaehyo wrote:[You must be registered and logged in to see this image.]
1* (2² * x^4*2)/ (5² * y²)
(4*x^8 )/(25y²)
Eisenmeteor Posts : 27
Join date : 20120714
Age : 27
Booo~
2[3(b5)(b^2+b+3)]
what i did was distribute the three and negative sign, 2(3b15b^2b3)
now distribute the two, (6b302b^22b6)
add all the common numbers together, (4b362b^2)
rearrange the numbers in order and answer is: 2b^2+4b36
DONE
if you have to simplify it more then take out the common factor of negative 2 to get : 2(b^2+2b18)
what i did was distribute the three and negative sign, 2(3b15b^2b3)
now distribute the two, (6b302b^22b6)
add all the common numbers together, (4b362b^2)
rearrange the numbers in order and answer is: 2b^2+4b36
DONE
if you have to simplify it more then take out the common factor of negative 2 to get : 2(b^2+2b18)
Yaichi Posts : 4
Join date : 20120821
Age : 26
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
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find an expression for the area of the shaded portion of the figure[b]
find an expression for the area of the shaded portion of the figure[b]
Jaehyo Posts : 64
Join date : 20120724
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
Jaehyo wrote:[You must be registered and logged in to see this image.]
find an expression for the area of the shaded portion of the figure[b]
Shaded portion area = Whole area  White area
S = [3x(3x+10)][x*(x+4)]
S = (9x²+30x)(x²+4x)
S = 8x²+26x
Eisenmeteor Posts : 27
Join date : 20120714
Age : 27
How many jelly coins?
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airmanof1 Alpha
 Posts : 69
Join date : 20120714
Age : 41
Location : North Carolina USA
slowpoke.jpg
erm... sry for necroing, either way deal with it. First and foremost for everyone having issues or simply looking for solutions for math problems visit [You must be registered and logged in to see this link.] and input whateve the math formula is and voila, computer magic is made. This is a hugely powerful tool that can solve diferencial equations among many other complex math formulas, just oughta put it out there. Also air... the music you used in that video...is perfect...
input example: ((3^7)*(x^5))/((3^3)(x^3)) this is for the second one you posted Jae. Do try it out, you have graphs, derivatives and whatever else you can think off done for you, and the free version even allows you to see the answer step by step ( they limit it to 3 times a day though ). Either way, it's a must if you have any advanced or simple math classes, so be sure to give it a try.
input example: ((3^7)*(x^5))/((3^3)(x^3)) this is for the second one you posted Jae. Do try it out, you have graphs, derivatives and whatever else you can think off done for you, and the free version even allows you to see the answer step by step ( they limit it to 3 times a day though ). Either way, it's a must if you have any advanced or simple math classes, so be sure to give it a try.
ShadowDx Posts : 76
Join date : 20120713
Age : 26
Location : Lamego
Re: CALLING ALL MATH GEEKS QQ (Algebra II here)
ShadowDx wrote: erm... sry for necroing, either way deal with it. First and foremost for everyone having issues or simply looking for solutions for math problems visit [You must be registered and logged in to see this link.] and input whateve the math formula is and voila, computer magic is made. This is a hugely powerful tool that can solve diferencial equations among many other complex math formulas, just oughta put it out there. Also air... the music you used in that video...is perfect...
input example: ((3^7)*(x^5))/((3^3)(x^3)) this is for the second one you posted Jae. Do try it out, you have graphs, derivatives and whatever else you can think off done for you, and the free version even allows you to see the answer step by step ( they limit it to 3 times a day though ). Either way, it's a must if you have any advanced or simple math classes, so be sure to give it a try.
Thanks!
Jaehyo Posts : 64
Join date : 20120724
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